Question

Find the zeroes of the quadratic polynomial and verify relationships between the zeroes and coefficient 1) x square-2x-8

Answer 1

Hiii friend,

P(X) = X²-2X-8


=> X²-4X+2X-8


=> X(X-4) +2(X-4)

=> (X-4) (X+2) = 0

=> (X-4) = 0 OR (X+2) = 0


=> X = 4 OR X = -2

4 and -2 are the two zeros of the polynomial X²-2X-8


Let Alpha = 4 and beta = -2


Relationship between the zeros and Coefficient.



Sum of zeros = (Alpha + beta) = (4+(-2) = 4-2 = 2/1 = -(Coefficient of X)/Coefficient of X².


And,


Product of zeros = (Alpha × beta) = 4 × -2 = Constant term/Coefficient of X².



HOPE IT WILL HELP YOU...... :-)