Find the zeroes of the quadratic polynomial and verify the relationship between the zeroes and the coefficients of the polynomial 6x square -3 -7x
Answers
Answer:
The answer would be to take the polynomial, and put it in a equation that says it's equal to zero, and then solve it for the unknown quantity (which is probably x). If it's a quadratic equation, for example, you could use the Quadratic Formula to find what x is (and it might have 0, 1, or 2 answers). I'll paste that in below, in case it's what you're working on.
Another part of the answer is that << 6square-15' >> is not so clear. It might mean "six squared, minus 15 feet" for example, or maybe " six with -15 as an exponent ", or some other possibilities - and, without knowing the polynomial, so that we can't see how this would be a coefficient, it's mighty hard to tell what its relationship with the zeros would be: that would depend on where the coefficient occurs, within the polynomial.
Sorry for giving you such a useless answer, but I'm afraid it's the best I can do. :-)
P(x)=6x^2-7x-3
P(x)=6x^2+2x-9x-3
P(x)=2x(3x+1)-3(3x+1)
P(x)=2x-3=0. 3x+1=0
P(x)=2x=3. 3x=-1
P(x)=3/2. x=-1/3
3/2,-1/3 are the zeroes of the quadratic polynomial 6x^2-7x-3
Relationship between zeroes and coefficients
Sum of zeroes=-(coefficient of x)/coefficient of x^2=-(-7)/6=7/6
Product of zeroes=constant term/coefficient of x^2=-3/6=-1/2
I hope it's help you
Plz mark my answer as a brainliest answer