Question

find the zeroes of the quadratic polynomial ax^2 +(a+ b)x + b

Answer 1

Step-by-step explanation:

ax^2 + ax + bx +b= 0

→x(ax+b)+ 1(ax+b)= 0

→(x+1)(ax+b)= 0.

→x = -1 or -b/a are the required zeros

Answer 2

Here is ur answer

$a {x}^{2} + (a + b)x + b \\ = > a {x}^{2} + ax + bx + b \\ = > ax(x + 1) + b(x + 1) \\ = >( ax + b)(x + 1) \\ \: \: \: \: \: for \: zeros \: \\ ax + b \: = 0 \\ x = - \frac{b}{a} \\ now \: x + 1 = 0 \\ x = - 1 \\ hope \: it \: helps \: u$

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