find the zeroes of the quadratic polynomial of 3x²-x-4and verify the relationship between the zeroes and the coefficients
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Answer:
-4and3
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Solution
▪︎ 3x²-x-4
= 3x²-(4-3)x-4=0
= 3x²-4x+3x-4=0
= x(3x-4)+1(3x-4)=0
= (3x-4)(x+1)=0
=x=4/3, x=-1
Sum of zeros = -b/a
= 4/3+(-1)= -(-1)/3
= 1/3= 1/3
product of zeros = c/a
4/3= -(-4/3)
4/3=4/3
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