find the zeroes of the quadratic polynomial p(x) = 2x²-5x +7
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2x^2-7x+2x-7
2x^2+2x-7x-7
2x (x+1)-7 (x+1)
(2x-7)(x+1)
x=7/2 or x=-1
2x^2+2x-7x-7
2x (x+1)-7 (x+1)
(2x-7)(x+1)
x=7/2 or x=-1
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4
Hope this helps...!!!
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