Question

find the zeroes of the quadratic polynomial p(x) =X2+7x+12

Answer 1

Heya!

Here is yr answer.......


p(x) = x² + 7x + 12

let p(x) = 0

x² + 7x + 12 = 0

x² + 4x + 3x + 12 = 0

x(x+4) + 3(x+4) = 0

(x+4) (x+3) = 0



(x+4) = 0 => x = -4

(x+3) = 0 => x = -3

Therefore, -4 and -3 are the zeros of the polynomial p(x)


Hope it hlpz...

Answer 2

Hey mate, here is your answer...

p(x) = x^2 + 7x + 12
= x^2 + (4 + 3) x + 12
= x^2 + 4x + 3x + 12
= x (x + 4) +3 (x + 4)
= (x + 4) (x + 3)
= x = -3 or x = -4
are the zeros of quadratic polynomial..

Hope, it will help you...

Keep asking...

If really helps, please mark my answer as Brainliest one....