Question

.Find the zeroes of the quadratic polynomial x2

– 13x + 40 and verify the relationship

between the zeroes and the coefficients of the polynomial.

please answer fast i am giving prelims exam​

Answer 1

Solution :-

→ x² - 13x + 40 = 0

→ x² - 5x - 8x + 40 = 0

→ x(x - 5) - 8(x - 5) = 0

→ (x - 5)(x - 8) = 0

→ x = 5 and 8 .

therefore, zeroes of the quadratic polynomial are 5 and 8 .

Now, First Relation is :-

→ Sum of Zeros = - (coefficient of x) /(coefficient of x²)

Putting both values ,

→ 5 + 8 = -(-13)/1

→ 13 = 13 { Hence Verified. }

Second Relation :-

→ Product Of Zeros = Constant Term / (coefficient of x²)

Putting both Values ,

→ 8 * 5 = (40) / (1)

→ 40 = 40 { Hence Verified. }

Learn more :-

https://brainly.in/question/18390601

Answer 2

Answer:

answer is ( x-8 ) ( x-5)

Step-by-step explanation:

x2+13x+40

x2+5x+8x+40

x(x-5) -8 (x-5)

(x-8) (x-5)

I hope it will help you

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