Question

find the zeroes of the quadratic polynomial x2-2x-8

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Answer 1

$\boxed{\huge{\red{Answer}}}$

$= {x}^{2} - 2x - 8 \\ = {x}^{2} - 4x + 2x - 8 \\ = x(x - 4)2(x - 4) \\ = (x + 2)(x - 4)$

x = -2 , x = 4