Question

find the zeroes of the quadratic polynomial x²+x-12 and verify the relation between the zeroes and the coefficient

please answer this question fast​

Answer 1

p(x) = x² + x - 12

☛ x² + 4x - 3x - 12

☛ x( x + 4) - 3( x + 4)

☛ (x + 4)(x - 3)

Zeroes are -4 and 3

p(x) = x² + x - 12

☛ Sum of zeroes = - (coefficient of x) / (coefficient of x² )

☛ -4 + 3 = - ( 1) / 1

☛ -1 = -1

Also,

☛ Product of zeroes = - ( constant term ) / (coefficient of x² )

☛ -4 × 3 = - 12/1

☛ -12 = -12

Hence, Proved.