Find the zeroes of the quadratic polynomial x2+x-12 and verify the realtuonship
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we have to find the zeroes of the quadratic polynomial, x² + x - 12.
x² + x - 12 = 0
⇒x² + 4x - 3x - 12 = 0
⇒x(x + 4) - 3(x + 4) = 0
⇒(x - 3)(x + 4) = 0
⇒x = 3, -4
sum of zeroes = - coefficient of x/coefficient of x²
sum of zeroes = 3 - 4 = -1
- coefficient of x/coefficient of x² = -1/1 = -1
LHS = RHS
product of zeroes = constant/coefficient of x²
product of zeros = 3 × -4 = -12
constant/coefficient of x² = -12/1 = -12
LHS = RHS
hence verified
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