Question

Find the zeroes of the quadratic polynomial y^2+7y+10 and verify the relationship between the zeroes and the coefficient

Answer 1

Answer:

y^2 +7y+10

=y^2+(5+2)y+10

=y^2 +5y+ 2y+10

=y(y+5)+2(y+5)

=(y+5) (y+2)

either, (y+5)=0

y= -5

or, (y+2)=0

y= -2

Step-by-step explanation:

sum of the zeroes = -5+(-2) = -7= -(coefficient of x)/(coefficient of x^2)

product of the zeroes = -5×(-2) =10

= constant term/(coefficient of x^2)