Question

find the zeroes of the questions polynomial x square-2x-8.​

Answer 1

Step-by-step explanation:

x² - 2x - 8

x² - 4x + 2x - 8

x(x-4) + 2(x-4)

(x+2)(x-4)

Answer 2

$\huge\mathbb{SOLUTION:-}$

$\sf\:\:\hookrightarrow {\blue{x{}^{2}-2x-8=0}}\\ \\ \sf:\leadsto \:\:\:\:taking\:factor\:of\:8= 4\times 2\\ \\ \sf:\implies x{}^{2}-(4-2)x-8=0\\ \\ \sf:\implies x{}^{2}-4x+2x-8=0\\ \\ \sf:\implies x(x-4)+2(x-4)=0\\ \\ \sf:\implies (x-4)(x+2)=0$

• Now the Zero's of polynomial

$\sf\bullet x-4=0\\ \sf:\implies x=4\\ \\ \sf\bullet x+2=0\\ \sf:\implies x=(-2)$

$\boxed{\sf{Zero's\:of\: polynomial= 4\:and\:(-2)}}$