Question

find the zeroes of x^2-3x+1​

Answer 1

Answer:

x^2 - 3x + 1 = 0

By quadratic formula: $\tt{\frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}}$

Here, b = 3

a = 1

c = 1

=> $\tt{\frac{3 \pm \sqrt{9 - 4}}{2}}$

=> $\tt{\frac{3 \pm \sqrt{5}}{2}}$

These are the two roots.

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