Question

Find the zeroes of x^2+99x+127 by middle term splitting

Answer 1

Answer:

Step-by-step explanation:

we can find the zeros by quadratic formula

that is (-b $\frac{+}{-}$ $\sqrt{b^{2} -4ac}$)/2a

where a = 1,b = 99,c = 127

so by putting value we can find the answer

Answer 2

Complete question:

Find the zeroes of x²+99x+1260 by middle term splitting

Answer:

The zeros of x²+99x+1260 are -84 and -15

Step-by-step explanation:

To find,

The zeroes of the polynomial x²+99x+1260  by middle term splitting.

Solution:

Recall the concepts:

The zeroes of the polynomial are those values of the variable which satisfies the given equation

To find the zeroes, we need to factorize the given polynomial

To factorize the polynomial by middle term splitting, we need to find two integers such that their sum = 99 and product = 1260

Two such numbers are 84 and 15

Then we have,

x²+99x+1260 =  x²+84x+15x+1260

= x(x+84) +15(x+84)

= (x+84)(x+15)

x²+99x+1260 =  (x+84)(x+15)

To find the zeros,

x²+99x+1260 = 0 ⇒ (x+84)(x+15) = 0

⇒ x = -84 and x = -15

∴ The zeros of x²+99x+1260 are -84 and -15

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