find the zeroes of x²-2
Answers
Answered by
3
x²-2=0
x²=2
x=(plus minus)√2
Answered by
3
Answer:
Solution :
Let p(x) = x² - 2
To find zeroes of p(x) ,
We have to take p(x) = 0
=> x² - 2 = 0
=> x² = 2
=> x = ±√2
Therefore ,
-√2 or √2 are two zeroes
of p(x).
Explanation:
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