Question

find the zeroes of x²-2x-15 and verify the relationship b/w zeroes and co - efficients​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

x²+3x-5x-15 =. 0

x(x+3) -5 ( x+3)=0

(x+3) (x-5) = 0

so the zeroes are, 5 and -3

=> alpha + beta = -b/a

5 +(-3) = 2 = -(-2)/1 = 2

=> alpha × beta = c/a

5 × (-3) = -15 = -15/1