Question

find the zeroes of x² -5x - 6 and
verify the relations between
the zeroes and its cofficient​

Answer 1

Answer:

HOW TO FIND?

Simply, split middle terms.

${x}^{2} - 5x - 6 \\ {x}^{2} - 6x + x - 6 \\ x(x - 6) + (x - 6) \\ (x - 6)(x + 1) \\ by \: equating \: these \: expression \: to \: zero \\ x - 6 = 0 \\ x = 6 \\ x + 1 = 0 \\ x = - 1 \\ two \: values \: of \: x \: 6 \: and \: - 1. \\ sum \: of \: zeroes \: = \frac{ - b}{a} \\ product \: of \: zeroes \: = \frac{c}{a} \\ according \: to \: answer \: \\ 6 + ( - 1) = 6 - 1 = 5 \\ 5 \: is \: sum \: of \: zeroes \\ by \: \: \: \frac{ - b}{a} = \frac{ - (- 5)}{1} = 5 \\ hence \: verified \\ product \: = 6 \times ( - 1) = - 6 \\ by \: \: \: \frac{c}{a} = \frac{ - 6}{1} \\ \frac{c}{a} = - 6$

Hence, proved

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