Question

find
the zeroes of x²+x-12
and verify the relationship between zeroes and coefficient​

Answer 1

x²+4x-3x-12=0

x(x+4)-3(x+4)=0

x=3. x=-4

$\alpha \times \beta = - 1 \div 12$

-12=-12. ...

Answer 2

Step-by-step explanation:

X^2+x-12=0

x^2+4x-3x-12=0

x(x+4)-3(x+4)=0

(x-3) (x+4)=0

Either,

x-3=0

x=3

Or,

x+4=0

x=-4

Proof,

let the roots be m and n,

We know,

mn =-12/1

-12

Again,

multiplying the mn in respect of their values,

mn =3×-4

=-12