Find the zeroes v2+4root3-15
Answers
Answered by
10
heya..!!!
i think some typing mistake
right questions is like that:+
v² + 4√3v - 15
=> v² + 5√3v - √3v - 15
=> v(v + 5√3) - √3(v + 5√3)
=> (v - √3)(v + 5√3)
hope it's help you
i think some typing mistake
right questions is like that:+
v² + 4√3v - 15
=> v² + 5√3v - √3v - 15
=> v(v + 5√3) - √3(v + 5√3)
=> (v - √3)(v + 5√3)
hope it's help you
Answered by
1
Hi ,
Let p( v ) = v² + 4√3v - 15,
To find the zeroes of p( v ) , we have
Take p( v ) = 0
Therefore ,
v² + 4√3v -15 = 0
v² + 5√3v - √3v - 15 = 0
v² + 5√3v - √3v - 5√3 × √3 = 0
v( v + 5√3 ) - √3 ( v + 5√3 ) = 0
( v + 5√3 ) ( v - √3 ) = 0
v + 5√3 = 0 or v - √3 = 0
v = - 5√3 or v = √3
Therefore ,
-5√3 , √3 are Zeroes of p( v )
I hope this helps you.
: )
Let p( v ) = v² + 4√3v - 15,
To find the zeroes of p( v ) , we have
Take p( v ) = 0
Therefore ,
v² + 4√3v -15 = 0
v² + 5√3v - √3v - 15 = 0
v² + 5√3v - √3v - 5√3 × √3 = 0
v( v + 5√3 ) - √3 ( v + 5√3 ) = 0
( v + 5√3 ) ( v - √3 ) = 0
v + 5√3 = 0 or v - √3 = 0
v = - 5√3 or v = √3
Therefore ,
-5√3 , √3 are Zeroes of p( v )
I hope this helps you.
: )
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