Question

Find the zeros 3x ​2 -4x+2

Answer 1

3x²-4x+2
We are going to use Sridharacharya's formula to find the zeros of the above equation.
α={-b+√(b²-4ac)}/2a
β={-b-√(b²-4ac)}/2a
α={4+√(16-24)}/6={4+√-8}/6=(2+√-2)/3
β={4-√(16-24)}/6={4-√-8}/6=(2-√-2)/3