Find the zeros 3x 2 -4x+2
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3x²-4x+2
We are going to use Sridharacharya's formula to find the zeros of the above equation.
α={-b+√(b²-4ac)}/2a
β={-b-√(b²-4ac)}/2a
α={4+√(16-24)}/6={4+√-8}/6=(2+√-2)/3
β={4-√(16-24)}/6={4-√-8}/6=(2-√-2)/3
We are going to use Sridharacharya's formula to find the zeros of the above equation.
α={-b+√(b²-4ac)}/2a
β={-b-√(b²-4ac)}/2a
α={4+√(16-24)}/6={4+√-8}/6=(2+√-2)/3
β={4-√(16-24)}/6={4-√-8}/6=(2-√-2)/3
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