Question

Find the zeros and verify the relationship between the zeros and the coefficient



please solve this two questions in notes it's urgent​

Answer 1

Answer:

(x - a)(x-b) are the factor of polynomial a x square + b x + 3

Step-by-step explanation:

hope it helps you

Answer 2

1) p(x) = x² + 2√2x - 6

We can find the zeros by factorization [ by splitting the middle terms ]

x² + 2√2x - 6

x² + 3√2x - √2x - 6

x [ x + 3√2 ] - √2 [ x+ 3√2]

[ x - √2 ] [ x+ 3√2]

the zeros are = √2 and -3√2

α = √2

β = -3√2

a = 1

b = 2√2

c = -6

Sum of zeros = √2 + -3√2 = -2√2 = -b/a [ -b/a = -2√2 ]

Product of zeros = √2 × -3√2 = - 6 = c/a [c/a = -6/1 = -6]

2 ) is in the photos I have written my handwriting is not good at all but understanding.