find the zeros and verify the relationship between zeros and coofficients :-
4u²+8u
ans it asap
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6
hi friend,
given , 4u²+8u=4u(u+2)
so,the zeros of the polynomial are zero and -2
sum of zeros =-2=-x coefficient/x² coefficient =-8/4=-2
product of zeros =0=constant/x²- coefficient =0
hence verified
I hope this will help u ;)
given , 4u²+8u=4u(u+2)
so,the zeros of the polynomial are zero and -2
sum of zeros =-2=-x coefficient/x² coefficient =-8/4=-2
product of zeros =0=constant/x²- coefficient =0
hence verified
I hope this will help u ;)
dhathri123:
ya
Answered by
2
I hope this helps u
:).
:).
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