Question

find the zeros by splitting the middle term

Answer 1

Hello friend

√3x²-11x+6√3=0

√3x²-9x-2x+6√3=0

√3x(x-3√3)-2(x-3√3)=0

(x-3√3)(√3x-2)=0

x-3√3=0

x=3√3

√3x-2=0

x=2/√3

The zeroes of the polynomial are 3√3 and 2/√3

Answer 2

√3x²-11x+6√3
(√3)(6√3)=18
18=9×2

=>√3x²-11x+6√3=0
=>√3x²-9x-2x+6√3=0
=>√3x(x-3√3)-2(x-3√3)=0
=>(√3x-2)(x-3√3)=0

we know that,
if ab=>
a=0 or b=0
=>(√3x-2)=0
x=2/√3

OR

(x-3√3)=0
x=3√3 ANSWER...

Hope this helps:-))