Question

find the zeros for each of the following :

y= 2x2-x-6

Answer 1

Answer:

y=2x²-x-6

y=2x²-4x+3x-6

y=2x(x-2)+3(x-2)

y=(2x+3)(x-2)

therefore, zeroes are

-3/2 & 2

Answer 2

Answer:

$-\frac{3}{2} and 2$

Step-by-step explanation:

y = 2x² - x - 6

By splitting the middle term,

2x² - 4x + 3x - 6 = y

⇒ 2x(x-2) + 3(x-2) = y

⇒ (2x+3)(x-2) = y

∴ The zeroes of the polynomial are $-\frac{3}{2}$ and $2$.

Hope this helped!

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