find the zeros for each of the following :
y= 2x2-x-6
Answers
Answered by
2
Answer:
y=2x²-x-6
y=2x²-4x+3x-6
y=2x(x-2)+3(x-2)
y=(2x+3)(x-2)
therefore, zeroes are
-3/2 & 2
Answered by
1
Answer:
Step-by-step explanation:
y = 2x² - x - 6
By splitting the middle term,
2x² - 4x + 3x - 6 = y
⇒ 2x(x-2) + 3(x-2) = y
⇒ (2x+3)(x-2) = y
∴ The zeroes of the polynomial are and .
Hope this helped!
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