Question

find the zeros of 2x^2-5x-12 and find relationship​

Answer 1

Answer:

{ - 3/2 , 4 }

Step-by-step explanation:

2x² - 5x - 12 = 0

D = (- 5)² - 4×(- 12)×2 = 25 + 96 = 11²

$x_{12}$ = ( - b ± √D) / 2a = (5 ± 11) ÷ 4

$x_{1}$ = 4

$x_{2}$ = - 3/2

$x_{1}$ + $x_{2}$ = - $\frac{b}{a}$

$x_{1}$ × $x_{2}$ = $\frac{c}{a}$

$x_{1}$ + $x_{2}$ = 4 - 1.5 = 2.5 = - ( $\frac{-5}{2}$ )

$x_{1}$ × $x_{2}$ = 4 × (- 1.5) = - 6 = $\frac{-12}{2}$