Question

find the zeros of 3 X square + 4 root 3 X + 4​

Answer 1

We have,

3x² + 4√3x + 4

= 3x² + 2√3x + 2√3x + 4

= √3x(√3x + 2) + 2(√3x + 2)

= (√3x + 2)(√3x + 2)

= (√3x + 2)²

So, √3x + 2 = 0

=> x = -2/√3 = -2√3/3

Hope, it'll help you.....

Answer 2

Answer:

$= \frac{-2}{3}$

Step-by-step explanation:

$d = {b}^{2} - 4ac$

$d = {(4 \sqrt{3} )}^{2} - 4 \times 3 \times 4$

$d = 48 - 48 = 0$

$x = \frac{ - b \frac{ + }{ } \sqrt{d} }{2a}$

$x = \frac{ - (4 \sqrt{3}) \frac{ + }{} \sqrt{0} }{2 \times 3}$

$x = \frac{ - 4 \sqrt{3} }{6}$

$x = \frac{ - 2}{ \sqrt{3} }$

⭐Hope it helps⭐

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