Question

find the zeros of 3x^2 - 2x - 6​

Answer 1

Answer:

Step-by-step explanation:

3x^2 - 2x - 6 = 0

alpha = m

beta = n

m + n = 2 / 3 mn

= - 6 / 3

= - 2 (m+n)^ 2 - 4mn

= (m-n)^2

= (2 / 3)^2 - 4(-2)

= 4 / 9 + 8

Answer 2

Answer:

0.33 , -6.33

Step-by-step explanation:

this answer will solve with help of graph