Math, asked by akshatmaheshwari7320, 10 months ago

find the zeros of 3y*2-3√2+1

Answers

Answered by urfriend55

0

Answer:

write question in correct manner

Answered by ranjithkumar9207

0

Answer:

2.75

Step-by-step explanation:

3y*2-3√2+1=0

3*2-3√2+1=0/y

2.75=0

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