Find the zeros of 4√5x^2-17x-3√5 and verify the relation between the zeros and coefficient of the polynomial.
[ Remember that there's minus(-) sign before 3 root 5]
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Answered by
35
hi mate
here is ur answer
4√5x^2 - 17x -3√5
4√5x^2 + 20x - 3x - 3√5
4√5x ( X+√5) -3 ( X+√5)
(X+√5) ( 4√5x - 3)
➡️X=(-√5)
➡️X=3/4√5
sum = -b/a= -(-17)/4√5 = 17/4√5
product= c/a= -3√5/4√5= (-3/4)
I hope this will help you
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here is ur answer
4√5x^2 - 17x -3√5
4√5x^2 + 20x - 3x - 3√5
4√5x ( X+√5) -3 ( X+√5)
(X+√5) ( 4√5x - 3)
➡️X=(-√5)
➡️X=3/4√5
sum = -b/a= -(-17)/4√5 = 17/4√5
product= c/a= -3√5/4√5= (-3/4)
I hope this will help you
⚛️mark as brainliest ⚛️
Answered by
3
Answer:
4√5x^2 - 17x -3√5
4√5x^2 + 20x - 3x - 3√5
4√5x ( X+√5) -3 ( X+√5)
(X+√5) ( 4√5x - 3)
➡X=(-√5)
➡X=3/4√5
sum = -b/a= -(-17)/4√5 = 17/4√5
product= c/a= -3√5/4√5= (-3/4)
Step-by-step explanation:
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