Question

find the zeros of 6 x square +11x+3​

Answer 1

Step-by-step explanation:

Given equation is 6x2 + 11x + 3 = 0.

⇒ 6x2 + 9x + 2x + 3 = 0.

⇒ 3x (2x + 3) + 1(2x + 3) = 0.

⇒ (2x +3) (3x + 1) = 0.

Now, either 2x + 3 = 0 ⇒ x = −32.

Or, 3x + 1= 0 ⇒ x = −13.

Answer 2

Step-by-step explanation:

$6x^{2} +11x+3\\6x^{2} +2x+9x+3\\(6x^{2}+2x)+(9x+3)\\2x(3x+1)+3(3x+1)\\(2x+3) (3x+1)\\2x+3=0 , 3x+1=0\\2x=0-3 , 3x=0-1\\2x=-3 , 3x=-1\\x=\frac{-3}{2} ,x=\frac{-1}{3}$