Find the zeros of 6x^2+7√2x+4
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6x²+7√2x+4
=6x²+4√2x+3√2x+4
=2x(3x+2√2)+√2(3x+2√2)
=(3x+2√2)(2x+√2)
=6x²+4√2x+3√2x+4
=2x(3x+2√2)+√2(3x+2√2)
=(3x+2√2)(2x+√2)
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