Question

find the zeros of a polynomial p(x) =5x²+3x-4 is

Answer 1

Answer:

-3+-root89/10

plz like my answer

Answer 2

ANSWER:

Given

• p( x ) = 5x² + 3x - 4

To find the zeroes we have

Using quadratic equation formula

Quadratic equation formula ↓

${ \rm{ \red{ \to} \purple {x} = \green{\dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} }}}$

Here,

a = 5 , b = 3 , c = -4

${ \rm{ \implies \frac{ - 3 \pm \sqrt{ {3}^{2} - 4(5)( - 4)} }{2(5)} }}$

$\implies \frac{ - 3 \pm \sqrt{9 + 80} }{10}$

$\implies \frac{ - 3 + \sqrt{89} }{10} (or) \frac{ - 3 - \sqrt{89} }{10}$

Hence,

Roots of the given

quadratic equation are -3 + √89/10 & -3 - √89/10

Note

• We can't solve this using factorisation because the middle term can't be splited because it a prime number