Question

Out of 0.1molal aqueous solution of glucose and 0.1 molal aqueous solution of kcl which one will have higer boiling point

Answer 1

Answer:

0.1m KCl will have higher boiling point.

Explanation:

Elevation in boiling point = Vant hoff factor × molal boiling point constant × molality

(ΔTb) = (i)(Kb)(m)

and in the given situation, molality is given to be same(0.1). And Kb will be same too, since it only depends on the solute, which is water in both cases (aqueous solution), but 'i' for KCl is 2, since it dissociates into 2 ions K⁺ and Cl⁻, while Sugar or glucose does not dissociate, so 'i' remains 1

Thank you!!

Answer 2

Answer:

Explanation:

We know,Elevation of boiling point is proportional to Vant Hoff factor(when molality is same)Vant Hoff factor=No. of particles after dissociation/No. of particles before dissociation.For KCl,it is 3, and for glucose it is 1(Since, glucose is covalent)So,0.1m KCl will have higher boiling point.