Question

find the zeros of a polynomial x cube minus 2 x square - x + 2

Answer 1

hope it helps.......

Answer 2

Answer:

$\text{1, -1, 2 are the zeroes of the polynomial }x^3-2x^2-x+2$

Step-by-step explanation:

Given the cubic polynomial

$P(x)=x^3-2x^2-x+2$

we have to find the zeroes of the polynomial

$P(x)=x^3-2x^2-x+2$

By hit and trial method put x=1

$P(1)=1^3-2(1)^2-1+2$

$p(1)1-2-1+2=0$

which implies (x-1) is the factor of given polynomial or 1 is the zero of polynomial.

By synthetic division shown in attachment

$x^3-2x^2-x+2=(x-1)(x^2-x-2)$

$(x-1)(x^2-2x+x-2$

$(x-1)(x(x-2)+1(x-2))$

$(x-1)(x+1)(x-2)$

Hence, the zeroes of polynomial are

x-1=0 ⇒ x=1

x+1=0 ⇒ x=-1

x-2=0 ⇒ x=2