Find the zeros of each of the following quadratic polynomials and verify the
relationship between the zeros and their co-efficients: + 10x + 7
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Answer:
3x² + 10x + 7
3x² + 7x + 3x + 7
x(3x + 7) + 1 (3x + 7)
3x + 7 (x + 1)
Therefore of the zeroes are
x = -7/3 and
x = -1
Sum of zeroes = -b/a [ comparing with ax² + bx + c ]
-7/3 + (-1)
= -10/3
= -(10)/3 = -b/a
Product of zeroes = c/a [ ' ' ]
-7/3(-1)
=7/3
=c/a
[ a is co eff of x² and b is co eff of x and c is constant ]
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