Math, asked by HumanBean23, 13 days ago

Find the zeros of each of the following quadratic polynomials and verify the
relationship between the zeros and their co-efficients: 3x^{2} + 10x + 7

Answers

Answered by CuriousLearner007
1

Answer:

3x² + 10x + 7

3x² + 7x + 3x + 7

x(3x + 7) + 1 (3x + 7)

3x + 7 (x + 1)

Therefore of the zeroes are

x = -7/3 and

x = -1

Sum of zeroes = -b/a [ comparing with ax² + bx + c ]

-7/3 + (-1)

= -10/3

= -(10)/3 = -b/a

Product of zeroes = c/a [ ' ' ]

-7/3(-1)

=7/3

=c/a

[ a is co eff of x² and b is co eff of x and c is constant ]

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