Question

Find the zeros of :
(i) 6x^2-7x -3
(ii) 4x^2-4x +1

Answer 1

Answer:

I) 6x²-7x-3

⇒6x²+2x-9x-3=0

⇒2x(3x+1)-3(3x+1)=0

⇒(2x-3)(3x+1)=0

⇒x=3/2,x=-1/3

ii) 4x²-4x+1

4x²-2x-2x+1

⇒2x(2x-1)-1(2x-1)=0

⇒(2x-1)(2x-1)=0

⇒x=1/2,x=1/2

Answer 2

Answer:

1..x=3/2,-1/3. 2..x=1/2,1/2

Step-by-step explanation:

6x^2-7x-3=0

6x^2-9x+2x-3=0

3x(2x-3)+1(2x-3)=0

(2x-3)(3x-1)=0

Reqd zeros ---

2x-3=0. 3x+1=0

x=3/2. x=-1/3

4x^2-4x+1=0

4x^2-2x-2x+1=0

2x(2x-1)-1(2x-1)=0

(2x-1)(2x-1)=0

reqd zeros..

2x-1=0

x=1/2