find the zeros of (I) 6x^2-7x-3 (II) 4x^2-4x+1
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Answered by
2
Answer:
I) 6(0)^2-7(0)-3
6(0)-7(0)-3
0-0-3
= -3
ii) 4(0)^2-4(0)+1
4(0)-4(0)+1
0-0+1
=1
please mark the brain list answer.
Answered by
1
i) -1/3,3/2
ii) 1/2 , 1/2
Step-by-step explanation:
i) 6x² - 7x -3
=> 6x² - 9x + 2x -3 = 0
=> 3x(2x - 3) + 1(2x - 3) = 0
=> (3x + 1) (2x - 3) = 0
=> (3x + 1) = 0 , (2x - 3) = 0
=> x = -1/3. , x = 3/2
ii) 4x² - 4x + 1
=> 4x² - 2x - 2x + 1 = 0
=> 2x (2x - 1) - 1(2x - 1) = 0
=> (2x - 1) (2x -1) = 0
=> (2x - 1) = 0 , (2x -1) = 0
=> x = 1/2. , x = 1/2
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