Find the zeros of polynomial (2/x^2) - (5 / x )+ 2 = 0 by middle term splitting.
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2/x^2 - 5/x + 2 = 0
2/x ^2 - 4/ x - 1/x + 2 = 0
2/x ( 1/x - 2) -1 ( 1 /x - 2) = 0
(2/x - 1) (1/x - 2) = 0
(2/x - 1) = 0
2/x = 1
x = 2 ans.
1/x - 2 = 0
1/x = 2
x = 1/2 ans.
2/x ^2 - 4/ x - 1/x + 2 = 0
2/x ( 1/x - 2) -1 ( 1 /x - 2) = 0
(2/x - 1) (1/x - 2) = 0
(2/x - 1) = 0
2/x = 1
x = 2 ans.
1/x - 2 = 0
1/x = 2
x = 1/2 ans.
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