Question

find the zeros of polynomial 6 x square - 3 and verify the relation between zeros and coefficient​

Answer 1

The equation is given to be : p(x) = 6x² - 3. To find the zeros of the given equation, Equate the given p(x) = 0. ⇒ 6x² - 3 = 0. Dividing each term of the equation by 3. ⇒ 2x² - 1 = 0. ⇒ 2x² = 1. ⇒ x² = 1/2. ...

⇒ α = 1/2 and β = -1/2. Now, α = 1/2. -b/a = -(-3)/6. ⇒ -b/a = 1/2.

So, α = -b/a. And, β = -1/2.

So, β = b/a.