Find the zeros of polynomial f(x)=x3-5x2-2x+24 , if it's given that the product of its two zeros of 12
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By relation we know that product of all zeroes is -d/a
let the three zeroes be a,b and c
and a*b= 12
now,
abc=-24 (by relation)
hence, c = -2
let c=x
x=-2
x+2=0
Now,by long division divide x+2 by the given equation
and we get x^2-7x+12 as the quotient
After middle term splitting we get x=4
x=3
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