find the zeros of polynomial of 4root 3xsq. + 5x-2root 3
Answers
Answered by
5
Answer:
root3/4
-2/root3
Step-by-step explanation:
4root3x^2 + 5x - 2root3 = 0
4root3x^2 + 8x - 3x - 2root3 = 0
4x(root3x +2) - root3(root3x + 2) = 0
(4x-root3)(root3x + 2 ) = 0
x = root3/4 and -2/root3
Answered by
10
4√3 x² +5x -2√3 =0
⇒4√3 x² +8x -3x -2√3=0
⇒4x(√3 x+2) -√3(√3x +2) =0
⇒(√3x +2)(4x -√3) =0
⇒(√3x +2) =0 or (4x-√3) =0
⇒x = -2/√3 or √3/4
Hope it helps
⇒4√3 x² +8x -3x -2√3=0
⇒4x(√3 x+2) -√3(√3x +2) =0
⇒(√3x +2)(4x -√3) =0
⇒(√3x +2) =0 or (4x-√3) =0
⇒x = -2/√3 or √3/4
Hope it helps
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