find the zeros of polynomial px=x²-3-2x
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x^2-3x+x-3 = 0
x(x-3)+1 (x-3) = 0
(x+1)(x-3) =0
so x =1,3
hope this helps you out!
x(x-3)+1 (x-3) = 0
(x+1)(x-3) =0
so x =1,3
hope this helps you out!
Answered by
0
Answer:
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Step-by-step explanation:
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