Question

the length of rectangle is 8 M less than twice its breadth if the perimeter of rectangle is 56 M find its dimensions

Answer 1

Let the breadth of rectangle(b) = x m
then length(l) = (2x-8) m
A/q,
      perimeter of rectangle = 56 m
⇒  2(l+b) = 56
⇒  2(2x-8+x) = 56
⇒    3x-8 = 28
⇒     3x =28+8
⇒     x = 36/3 = 12 m
therefore length(l) = 2x-8 =2×12 - 8 =16 meters
               breadth(b) = x = 12 meters
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Answer 2

let the breadth be x m
then length is 2x - 8 m

perimeter of a rectangle is 2(l+b)
therefore
2(2x-8+x)=perimeter
or,2(3x-8)=56
or,6x-16=56
or,6x=72
or,x=12


therefore the length is 2x-8=16m
&&&&&
breadth is x=12m

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