Question

find the zeros of polynomial x square2-8
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Answer 1

Answer:

${x}^{2} - 8 = 0$

${x}^{2} = 8$

$x = \pm2 \sqrt{2}$

$x = + 2 \sqrt{2 } \: \: and \: x = - 2 \sqrt{2} \: is \: the \: answer$

Answer 2

Answer:

x^2×2-8=0

x^2=8/2

x=under root 4

x=2