Question

find the zeros of quadratic polynomial (1) 4 x square - 3 x -1 (2) 3 x square + 4 x -4 (3) 5x square + 12 x + 7 (4) t cube -2t squared -15t Choose the correct answer​

Answer 1

Step-by-step explanation:

sorry can't help with the 4 number

Answer 2

Step-by-step explanation:

1. 4x² - 3x - 1

= 4x² - 4x + x - 1

= 4x (x - 1) + 1 (x - 1)

= (4x + 1) (x - 1)

Zeros are +1 and -1/4

2. 3x² + 4x - 4

= 3x² + 6x - 2x - 4

= 3x (x + 2) - 2 (x + 2)

= (3x - 2) (x + 2)

Zeros are -2 and +2/3

3. 5x² + 12x + 7

= 5x² + 5x + 7x + 7

= 5x (x + 1) + 7 (x + 1)

= (5x + 7) (x + 1)

Zeros are -1 and -7/5

4. t³ - 2t² - 15t + 0 ( But it is not quadratic Polynomial)

by t = 0

0³ - 2(0)² - 15(0) + 0

+0 is root of p(x)

t³ - 2t² - 15t + 0

t² (t - 0) - 2t² - 15t + 0

t² (t - 0) - 2t (t - 0) - 15t + 0

t² (t - 0) - 2t (t - 0) - 15 (t - 0)

(t - 0) (t² - 2t - 15)

(t - 0) (t² - 5t + 3t - 15)

(t - 0) (t (t - 5) + 3 (t - 5))

(t - 0) (t + 3) (t - 5)

Zeros are 0, -3 and +5.