find the zeros of quadratic polynomial 3 x square - x - 4
Answers
Answered by
9
Hola....!!!!
Here's ur ans.⬇
Quadratic equation = 3x^2 - x - 4
By middle term split ,
3x^2 - 4x + 3x - 4
x(3x - 4) + 1 (3x -4)
(x+1 ) (3x - 4)
x = -1
x = 4/3
✌Hope it helps
Here's ur ans.⬇
Quadratic equation = 3x^2 - x - 4
By middle term split ,
3x^2 - 4x + 3x - 4
x(3x - 4) + 1 (3x -4)
(x+1 ) (3x - 4)
x = -1
x = 4/3
✌Hope it helps
Anonymous:
batao pehle
Answered by
5
Hey friend...!! here's your answer
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3x^2 - x - 4 = 0
3x^2 - 4x + 3x - 4 = 0
x ( 3x - 4 ) + 1 (3x - 4) = 0
(x + 1) (3x - 4)
x + 1 =0
3x - 4 = 0
x = -1 and 4/3
So that zeroes of polynomial 3x^2 - x - 4 is -1 and 4/3
___________________
#Hope its help you dear#
☺
__________________________
_________________________
3x^2 - x - 4 = 0
3x^2 - 4x + 3x - 4 = 0
x ( 3x - 4 ) + 1 (3x - 4) = 0
(x + 1) (3x - 4)
x + 1 =0
3x - 4 = 0
x = -1 and 4/3
So that zeroes of polynomial 3x^2 - x - 4 is -1 and 4/3
___________________
#Hope its help you dear#
☺
__________________________
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