Find the zeros of quadratic polynomial
√3x²-8x+4√3
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Answer:
√3x²-8x+4√3
=√3x²-2x-6x+4√3
=x(✓3x-2)-2√3(√3x-2)
=(√3x-2)(x-2√3)
= x=2/√3 or x=2√3
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