find the zeros of quadratic polynomial 6x square - 3
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Heya HERE is your answer
6x² - 3
(_/6x - _/3) (_/6x + _/3)
x = _/3 / _/6
x = - _/3 / _/6
6x² - 3
(_/6x - _/3) (_/6x + _/3)
x = _/3 / _/6
x = - _/3 / _/6
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