Question

find the zeros of quadratic polynomial and verify x square - 10x + 25​

Answer 1

Answer:

x=5 or 5

Step-by-step explanation:

xsqu-10x+25=0

(x-5)wholesqu=0

so x=5or5

verification

sum of zeroes=10

product of zeroes=25

verified

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Answer 2

Let p(x)=x^2-10x+25

There for

Zero of the polynomial is the value of X

where p(x)=0

Put p(X)=0

To find it's root we factorise

${x}^{2} - 10x + 25 \\ = {x}^{2} - 5x - 5x + 25 \\ = x(x - 5) - 5(x - 5) \\ = (x - 5)(x - 5) \\ = \alpha = 5 \: \: \: and \: \gamma = 5 \\ =$

To verify

$sum \: of \: zeroes \: = \frac{ - b}{a} \\ = \alpha + \beta = \frac { - 10}{1} \\ \\ = 5 + 5 = 10$

$product \: of \: zeroes = \frac{c}{a} \\ = 5 \times 5 = 25 \times 1 \\ = 25 = 25$