Question

find the zeros of quadratic polynomial f(x)6x^2 -3

Answer 1

Bonjour!

$= > 6 {x}^{2} - 3 = 0 \\ \\ = > 6 {x}^{2} = 3 \\ \\ = > {x}^{2} = \frac{3}{6} \\ \\ = > {x}^{2} = \frac{1}{2} \\ \\ = > x = + \frac{1}{ \sqrt{2} } \: and \: - \frac{1}{ \sqrt{2} }$

Hope this helps...:)

Answer 2

Your answer is --

we have

6x^2 - 3

For zeroes

$6 {x}^{2} - 3 = 0 \\ \\ = > 6 {x}^{2} = 3 \\ \\ = > {x}^{2} = \frac{3}{6} = \frac{1}{2} \\ \\ = > x = \sqrt{ \frac{1}{2} } \: or \: - \sqrt{ \frac{1}{2} }$


【 Hope it helps you 】